Question

add
9/4 +8
..........​

Answer 1

Answer:

9+32/4

41/4

Step-by-step explanation:

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Answer 2

$\LARGE{\bf{\underline{\underline{Solution:-}}}}$

$\bf\dfrac{9}{4}+8$

$=\bf\dfrac{9}{4}+$$\bf\dfrac{8}{1}$

L.C.M = 4

$=\bf\dfrac{9 + 8\times 4}{4}$

$=\bf\dfrac{9 + 32}{4}$

$=\bf\dfrac{41}{4}$

$=\bf{{10.25}}$

Or,

$= 10\dfrac{1}{4}$

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$\boxed{\begin{minipage}{6 cm}\bf{\dag}\:\:\underline{\textsf{Fraction Rules :}}\\\\\bigstar\:\:\sf\dfrac{A}{B} + \dfrac{B}{C} = \dfrac{A+B}{C} \\\\\bigstar\:\:\sf{\dfrac{A}{B} - \dfrac{B}{C} = \dfrac{A-B}{C}}\\\\\bigstar\:\:\sf\dfrac{A}{B} \times \dfrac{C}{D} = \dfrac{AC}{BD}\\\\\bigstar\:\:\sf\dfrac{A}{B} + \dfrac{C}{D} = \dfrac{AD}{BD} + \dfrac{BC}{BD} = \dfrac{AD+BC}{BD} \\\\\bigstar\:\:\sf\dfrac{A}{B} - \dfrac{C}{D} = \dfrac{AD}{BD} - \dfrac{BC}{BD} = \dfrac{AD-BC}{BD}\\\\\bigstar \:\:\sf \dfrac{A}{B} \div \dfrac{C}{D} = \dfrac{A}{B} \times \dfrac{D}{C} = \dfrac{AD}{BC}\end{minipage}}$

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