Question

add it for me please......................

Answer 1

Hi friend!

$\frac{4}{5} ab^{3} + \frac{ - 2}{3} {ab}^{3} + \frac{1}{2} ab ^{3} + \frac{3}{4} ab^{3} \\ \\ = ( \frac{4}{5} - \frac{2}{3} + \frac{1}{2} + \frac{3}{4} )ab^{3}$
LCM = 60

$= \frac{(48 - 40 + 30 + 45) {ab}^{3} }{60} \\ \\ = \frac{83 {ab}^{3} }{6}$
$= {ab}^{3} \frac{23ab^{3} }{60}$

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