Add the additive inverse of (-12+16-42/3 of 7) to the product of -2,-3& -4
Answers
Additive inverse of a number,x , is the number ,y, when you add to x you get zero.
find the value of the terms in bracket(use steps of BODMAS):
-12+16 (-42/3 of 7= -98) = -12+16 -98
= 16-12-98
= 16-110
= -94
The additive number is that when added to (-)94 will give zero, hence it is (+)94
Therefore add 94 to product of -2,-3 and -4
product of -2,-3 and -4 = -2 x -3 x -4
= -24
Therefore add 94 to -24 = 94 + (-24)
= 94-24
= 70
The answer is 70
Hope this is helpful.
Answer:
The answer is 70
Step-by-step explanation:
First find the additive inverse of (-12 + 16 - 42/3 of 7)
Additive inverse of a number,x , is the number ,y, when you add to x you get zero.
find the value of the terms in bracket(use steps of BODMAS):
-12+16 (-42/3 of 7= -98) = -12+16 -98
= 16-12-98
= 16-110
= -94
The additive number is that when added to (-)94 will give zero, hence it is (+)94
Therefore add 94 to product of -2,-3 and -4
product of -2,-3 and -4 = -2 x -3 x -4
= -24
Therefore add 94 to -24 = 94 + (-24)
= 94-24
= 70
The answer is 70