add the following:
ab²+a²c, a²b+c²a, 2ab²+2a²b+ 2c²a
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Answers
Answered by
1
Answer:
a(b²-c²)+b(c²-a²)+c(a²-b²)
=ab²-ac²+bc²-a²b+a²c-b²c
=ab²-a²b-ac²+bc²+a²c-b²c
=ab(b-a)-c²(a-b)+c(a²-b²)
=-ab(a-b)-c²(a-b)+c((a+b)(a-b))
=(a-b)[-ab-c²+c(a+b)]
=(a-b)[-ab+cb-c²+ac]
=(a-b)[-b(c-a)-c(c-a)]
=(a-b)(b-c)(c-a)
Step-by-step explanation:
Answered by
1
Answer:
hope it helps nd sorry if it doesn't
Step-by-step explanation:
ab^2 + 2ab^2 + a^2b+ 2a^2b+ c^2a + 2c^2a + a^2c
= 3ab^2+ 3a^2b + 3c^2a + a^2c
= 3( ab^2 + a^2b + c^2a ) + a^2c
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