Question

add the following:
ab²+a²c, a²b+c²a, 2ab²+2a²b+ 2c²a
no spam plz
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Answer 1

Answer:

a(b²-c²)+b(c²-a²)+c(a²-b²)

=ab²-ac²+bc²-a²b+a²c-b²c

=ab²-a²b-ac²+bc²+a²c-b²c

=ab(b-a)-c²(a-b)+c(a²-b²)

=-ab(a-b)-c²(a-b)+c((a+b)(a-b))

=(a-b)[-ab-c²+c(a+b)]

=(a-b)[-ab+cb-c²+ac]

=(a-b)[-b(c-a)-c(c-a)]

=(a-b)(b-c)(c-a)

Step-by-step explanation:

Answer 2

Answer:

hope it helps nd sorry if it doesn't

Step-by-step explanation:

ab^2 + 2ab^2 + a^2b+ 2a^2b+ c^2a + 2c^2a + a^2c

= 3ab^2+ 3a^2b + 3c^2a + a^2c

= 3( ab^2 + a^2b + c^2a ) + a^2c