Question

add the following polynomials:- A) 3a^2+(4a^2-20)+(-68) , B)(5r+3)+(-6r-3​

Answer 1

Answer:

Suppose (a−b) and (c−d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below.

(a−b)×(c−d)=a×(c−d)−b×(c−d)=(a×c−a×d)−(b×c−b×d)

=ac−ad−bc+bd

Let,

a=(3/4)a,b=(2/3)b,c=4a,d=3b

Now, 

=(3/4)a×(4a+3b)+(2/3)b×(4a+3b)

=[((3/4)a×4a)+((3/4)a+3b)]−[(2/3)b×4a)+((2/3)b×+3b)]

=[3a2+(27+32/12)ab+2b2]

=[3a2+(59/12)ab+2b2]

Step-by-step explanation:

please give me a point amd please make me brainless I hope I can help you you have a good day

Answer 2

A. 7$a^{2}$-88    B. -r

A)3$a^{2}$+(4$a^{2}$-20)+(-68)

3$a^{2}$+4$a^{2}$-20-68    (simplified the brackets)

7$a^{2}$-88    (on solving the like terms )

B) (5r+3)+(-6r-3)

5r+3-6r-3   (simplified the brackets )

5r-6r+3-3 ( solve the like terms )

-r