Math, asked by rajmdiqbal4711, 7 months ago

add the following solve all of this I mark you siksha year ​

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Answered by pabitrasaud29
0

Answer:

Add the following expressions:

(i) x3−2x2y+3xy2−y3, 2x3−5xy2+3x2y−4y3

(ii) a4−2a3b+3ab3+4a2b2+3b4,−2a4−5ab3+7a3b−6a2b2+b4

ANSWER:

Adding the given expressions, we have

(i) x3- 2x2y + 3xy2- y3+ 2x3- 5xy2 + 3x2y- 4y3

Collecting positive and negative like terms together, we get

x3+ 2x3- 2x2y + 3x2y + 3xy2- 5xy2 - y3 - 4y3

= 3x3 + x2y - 2xy2 - 5y3

(ii) (a4- 2a3b + 3ab3 + 4a2b2 + 3b4) + (-2a4- 5ab3 + 7a3b - 6a2b2 + b4)

a4- 2a3b + 3ab3 + 4a2b2 + 3b4 - 2a4- 5ab3 + 7a3b - 6a2b2 + b4

Collecting positive and negative like terms together, we get

a4 - 2a4 - 2a3b + 7a3b + 3ab3 - 5ab3 + 4a2b2 - 6a2b2 + 3b4 + b4

= - a4 + 5a3b - 2ab3 - 2a2b2 + 4b4

Step-by-step explanation:

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Answered by vandanakalkal
0

Answer:

a) 5x^2 - 2 xy +3y^2

b) -2x^2y

c) 2abc+13a^2+21b

d) 3y^2+ 4

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