Question

add the product of (-16) and (-9) to the quotient of (-132) by 6

Answer 1

-16×-9+(-132)/6=144 - 22=122

Answer 2

Answer:

Addition of the product of (-16) and (-9) to the quotient of (-132) which when divided by 6, is 122.

Solution:

The product of (-16) and (-9)

$=(-16)\times(-9)=144$

So, the product of (-16) and (-9) is 144.

The quotient of (-132) by 6  

$= \frac {(-132)}{6}= -22$

The quotient of a number is determined by dividing the dividend by the given divisor.

By that, the quotient of (-132) is determined by dividing it by 6, and the quotient is -22.  

∴ The sum of the product of (-16) and (-9) to the quotient of (-132) by 6

$=144+(-22)=144-22\\\\=122$

Thus, the addition of the products and the quotient of the given numbers will result in the number 122.