Question

Add.
x+2y-3z, -3x+y+2z, 2x-3y+z​

Answer 1

Answer:

$(x + 2y - 3z) + ( - 3x + y + 2z) + (2x - 3y + z) \\ = x + 2y - 3z - 3x + y + 2z + 2x - 3y + z \\ = (x + 2x - 3x) + (2y + y - 3y) + ( - 3z + 2z + z) \\ = x(1 + 2 - 3) + y(2 + 1 - 3) + z( - 3 + 2 + 1) \\ = x(0) + y(0) + z(0) \\ = 0 + 0 + 0 \\ = 0$

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Thanks.

Answer 2

Answer:

0

Step-by-step explanation:

$\implies x+2y-3z-3x+y+2z+2x-3y+z$

$\implies x-3x+2x+2y+y-3y-3z+2z+2z$

$\implies 3x-3x+3y-3y-3z-3z$

$\implies 0+0+0$

$\implies 0$