Math, asked by Parth483120, 5 months ago


add
x² -2x²y + 3xy² - y³, 2y³ -3y²x +9x²y and -3x² +3x²y -9y³

Answers

Answered by Anonymous
12

\sf x^2 - 2x^2y + 3xy^2 - y^3 + 2y^3 - 3y^2x + 9x^2y - 3x^2 + 3x^2y - 9y^3

\sf = (x^2 - 3x^2) + (-y^3+2y^3-9y^3) + (3xy^2-3xy^2) + (9x^2y + 3x^2y - 2x^2y)

\sf = -2x^2 - 8y^3 + 0 + 10x^2y

\sf = 10x^2y - 2x^2 - 6y^3

Answered by haadyah94200
1

Answer:

this is formula

Step-by-step explanation:

x {}^{2} - 2 {x}^{2} + 3xy {}^{2} -  {y}^{3} + (2 {y}^{3}- 3 {y}^{2} x + 9x {}^{2} y)

x{}^{2} −2x {}^{2} +3xy {}^{2} −y {}^{3}  + 2y {}^{2} −3y {}^{2} x+9x {}^{2} y

use this step and it will br solve then when the ans will come add it with another line wich is after and in question.

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