add x2+2xy + y2 to sum of x2 - 3y2 and 2x2- y 2+9
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Given x2 + 2xy + y2, x2 – 3y2and 2x2 – y2 + 9. First we have to find the sum of x2 – 3y2 and 2x2 – y2 + 9 = (x2 – 3y2) + (2x2 – y2 + 9) = x2 + 2x2 – 3y2 – y2+ 9 = 3x2 – 4y2 + 9 Now, required expression = (x2 + 2xy + y2) + (3x2 – 4y2 + 9) = x2 + 3x2 + 2xy + y2 – 4y2 + 9 = 4x2 + 2xy – 3y2+ 9Read more on Sarthaks.com - https://www.sarthaks.com/682922/add-x-2-2xy-y-2to-the-sum-of-x-2-3y-2-and-2x-2-y-2-9
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