Question

addition of algebra expressions 2a_3b,4b+,5a_8b give me answers this question


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Answer 1

Answer:

answeR:

{}

\bf{{\underline{Given}}:}

Given

:

\sf{OD~is~the~bisector~of~∠BOC}OD is the bisector of ∠BOC

\sf\implies{∠BOD=∠COD=x}⟹∠BOD=∠COD=x

\bf{{\underline{To~find}}:}

To find

:

\sf{The~value~of~~‛x’}The value of ‛x’

\sf{~~~~~~~~~~ ∠COD+∠BOD+∠BOF=180°~~~~(Straight~line)} ∠COD+∠BOD+∠BOF=180° (Straight line)

\sf\implies{x+x+20=180}⟹x+x+20=180

\sf\implies{2x+20=180}⟹2x+20=180

\sf\implies{2x=180-20}⟹2x=180−20

\sf\implies{2x=160}⟹2x=160

\sf\implies{x={\dfrac{160}{2}}}⟹x=

2

160

\sf\implies{x={\green{\underline{\boxed{\bf 80°}}}}}⟹x=

80°

\bf\therefore{{\underline{Required~answer}}:}∴

Required answer

:

\sf{x={\green{\underline{\boxed{\bf 80°}}}}}x=

80°

Answer 2

Answer:

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