Question

additive inverse of a+ib=​

Answer 1

Concept:

A number's additive inverse is the value that, when added to the original number, yields a value of zero. It is what we add to a number to make it equal to zero. If the initial number is a, then its additive inverse is the negative of a, or -a, so that;

a+(-a) = a - a = 0

Example:

-10 is the additive inverse of 10, as 10 + (-10) = 0.

9 is the additive inverse of -9, as (-9) + 9 = 0.

Given:

a+ib

Find:

Find the additive inverse of a+ib

Solution:

Additive inverse of a+ib=-(a+ib)

                                       =-a-ib

Therefore,-a-ib is the additive inverse of a+ib

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Answer 2

Answer:

The additive inverse of a+ib = -(a+ib)= -a-ib.

Step-by-step explanation:

Given:a number a+ib.

To find: The additive inverse of a+ib.

Solution :

A complex number is of the form a+ib where a and b are real numbers . So the given number is a complex number with real part 'a' and imaginary part 'b'.

Additive inverse  

An additive inverse of a complex number is the value which when added to the original number gives zero.

For eg; 2+i3 +[-(2+i3)] = 2+i3-2-i3 = 0.

so additive inverse of 2+i3 is -(2+i3).

additive inverse is also called opposite or negation of the number.

Here a+ib +[-(a+ib)] = a+ib-a-ib =0.

Therefore -a-ib is the additive inverse of a+ib.

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