Question

Aditi borrowed an amount from bank as a loan.After 3 years he paid rs 4826 and settled the accounts.If the rate of interest is 9 present per annum, what sum did she borrow ​

Answer 1

Answer:

Step-by-step explanation:

4826×9=48.26×9×3=1,303.02

100×3

A=P+I=4826+1,303.02

=6,129.02

Answer 2

Answer:

The principal amount borrowed is Rs.3800.

Step-by-step explanation:

Given the time period, T = 3years    

The amount paid after 3 years, A = Rs. 4826

Rate of interest, R = 9%

Simple interest is given by the following formula:

$S.I. = \dfrac{P R T}{100}$

where R is the rate of interest per annum, T is the time period and P is the principal amount borrowed.

And the final amount paid is given by the sum of the principal amount and the interest paid i.e., $A=P+S.I.$

Substituting the simple interest formula,

$A=P+\dfrac{PTR}{100}$

Substituting the given values,

$\implies 4826=P+\dfrac{P\times3\times 9}{100}$

$\implies 4826=\dfrac{100P+27P}{100}$

$\implies 4826\times100=127P$

Thus, the principal amount is

$P=\dfrac{4826\times100}{127}$

   $=38\times100=\mbox{Rs}.~3800$

So, the principal amount borrowed is Rs.3800.

For more problems:

https://brainly.in/question/30376974?referrer=searchResults

https://brainly.in/question/13222350?referrer=searchResults