Aditya decided to collect the science marks of his class. The total number of students are 50. After collecting the data, he analysed the data and prepared a report on the science marks of his class. Using this report he drew the following graph:-{graph is in the image}
Answers
Formed class , Median = 49
Step-by-step explanation:
graph attached
Marks Studentsa
Class f cf
0 - 20 17 17
20 - 40 5 22
40 - 60 7 29
60 - 80 8 37
80 - 100 13 50
Median = 40 + 20(25 - 22)/7
= 40 + 60/7
= 48.6
or from graph ≈ ≈ 49 ( against 50/2 = 25 on y axis , x axis is between 48 - 50)
3 Median = Mode + 2 Mean
=> 3 * 49 = Mode + 2(52)
=> Mode = 43
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Aditya decided to collect the science marks of his class. The total number of students are 50.
The required graph is attached below.
i) Form the frequency distribution table for the data
Class Frequency
0 - 20 17
20 - 40 22
40 - 60 29
60 - 80 37
80 - 100 50
ii) Find the median marks of his class from the graph.
As the question is to find the median using the graph and not using the data provided, so we have,
N = ∑ f = 17 + 22 + 29 + 37 + 50 = 155
N/2 = 155/2 = 77.5
Therefore the median is given by,
50/2 = 25 (on y-axis)
Median = 49 (on x-axis)
(iii) Obtain the mode of the data if the mean mark is 52
We use the formula,
3 Median = Mode + 2 Mean
Given,
Mean = 52
3 × 49 = Mode + 2 × 52
147 = Mode + 104
Mode = 147 - 104
Mode = 43
