Question

Aditya left his house at 9:20 am and travelled at 75 km per hour . His brother left later and travelled along the same road at 90 km ped hour . They both arrived at the same destination at 3:20 pm. At what time did Aditya's brother leave home?

Answer 1

Let Aditya brother left home after x hours when Aditya left.
Distance covered by Aditya b/w time period of 9:20 am and 3:20 pm i.e. in 6 hours=75 ×6
similarly distance covered by his bro. in x hours=90 × x
as they arrived at same destination so distance covered by them be equal thus,
90× X=75 ×6
X=5
so after 5 hours His bro. left the house i.e. at 2:20 pm.


Hope it helps you

Answer 2

Step-by-step explanation:

its wroong. .........