Question

adjacent figure is triangular in shape and is semi circular at the bottom .find the total area of this figure

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Answer 1

Answer:

$h = \sqrt{{l}^{2} - {r}^{2} } \\ h = \sqrt{ {10}^{2} - {6}^{2} } = 8$

Total Area

$( \frac{1}{2} \times 12 \times 8) + \frac{1}{2} \pi \times {6}^{2}$