Adjacent sides of a rectangle are 15cm and 9 cm. Find the length of its diagonal.
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5 digonals of 15 cm and 9 cm
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Given :-
- AB = 15cm
- AC = 9cm
Aim :-
- To find the length of the diagonal.
Properties of a rectangle :-
- Opposite sides are equal
- Diagonals are equal
- The angle formed in the corners is 90°
Pythagoras theorem:-
We know that, in a right angled triangle, the base squared sumed with the height squared will be equal to the hypotenuse squared.
(base)² + (height)² = (Hypotenuse)²
Let us take ∆ACD.
- Base = CD = 15cm [opposite sides are equal]
- Height = AC = 9cm
The diagonal is the hypotenuse.
Substituting the values,
(15)² + (9)² = (AD)²
225 + 81 = (AC)²
306 = (AC)²
Transposing the power,
√306 = AC
Hence the diagonals are √306cm in length
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