Math, asked by abhin12393, 3 months ago

Adjacent sides of a rectangle are in the ratio 5 : 12, if the perimeter of the rectangle is 34 cm, find the length of the diagonal.​

Answers

Answered by shivamrana25660
83

Answer:

premiter of rectangle=2(l+b)

2(5x + 12x) = 34 \\ 2 \times (17x) = 34 \\ 17 x=  \frac{34}{2}  \\ 17 x= 17 \\  x= 1

so L=12,B=5

length of diagonal=

 {d}^{2}  =  {l}^{2}  +  {b}^{2}  \\  {d}^{2}  =  {12}^{2} +  {5}^{2}   \\ {d}^{2}   = 144 + 25 \\   {d }^{2} = 169 \\ d = 13

Answered by ShírIey
134

Given: The adjacent sides of a rectangle are in the ratio of 5 : 12. & The perimeter of the rectangle is 34 cm.

Need to find: The Length and Diagonal?

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀

Let's say, that the Length and Breadth of the given rectangle be 5x and 12x respectively.

⠀⠀⠀

\underline{\bf{\dag} \:\mathfrak{As\;we\;know\: that\: :}}⠀⠀⠀⠀

\star\;\underline{\boxed{\pmb{\sf{Perimeter_{\:(rectangle)} = 2(Length + Breadth)}}}}\\\\

\sf{We \;have}\begin{cases}\sf{\quad Length = \bf{5x}}\\\sf{\quad Breadth = \bf{12x}}\\\sf{\quad Perimeter =\bf{34\; cm}}\end{cases}\\\\

:\implies\sf 34 = 2\Big(5x + 12x\Big)\\\\\\

:\implies\sf 34 = 2 \times 17x\\\\\\

:\implies\sf 34 = 34x\\\\\\

:\implies\sf x = \cancel\dfrac{34}{34}\\\\\\

:\implies\underline{\boxed{\pmb{\frak{x = 1}}}}\;\bigstar\\\\

Therefore,

  • Length of the rectangle, 5x = 5(1) = 5 cm
  • Breadth of the rectangle, 12x = 12(1) = 12 cm

\therefore{\underline{\textsf{Hence, the Length and Breadth of rectangle are \textbf{5, 12 cm} respectively.}}}

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀

✇ Now, we've to find out the Diagonal of the rectangle. & To Calculate the Diagonal of rectangle formula is Given by —

\star\:\underline{\boxed{\pmb{\sf{Diagonal_{\:(rectangle)} = \sqrt{\Big(Length\Big)^2 + \Big( Breadth\Big)^2}}}}}\\\\

» Substituting the Values in the formula —

:\implies\sf Diagonal_{\:(rectangle)}  = \sqrt{(5)^2 + (12)^2} \\\\\\

:\implies\sf Diagonal_{\:(rectangle)}  = \sqrt{25 + 144}\\\\\\

:\implies\sf Diagonal_{\:(rectangle)}  = \sqrt{169}\\\\\\

:\implies{ \pmb{\underline{\boxed{\frak{ \mathsf{D}iagonal_{\:(rectangle)}  = 13}}}}}\;\bigstar\\\\

\therefore{\underline{\textsf{Hence, the Diagonal of the rectangle is \textbf{13 cm}.}}}

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