Math, asked by Anonymous, 9 hours ago

Please give right answer​

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Answered by ManishShah98
4

\small\red{\boxed{Question  = zeroes \: of \: p(z)  =  {z}^{2}  - 27 \: are}} \\  \\  \color{orange}solution :  -  \\  \\ \color{blue}p(z)  =  {z}^{2}  - 27 \\  \\ \color{blue}p(  3\sqrt{3} ) = ( 3\sqrt{3} ) {}^{2}  - 27 \\  \\ \color{blue} = 27 - 27 \\  \\ \color{blue} = 0 \\  \\ \color{purple} = zeroes \: of \: the \: polynomial \: is \: (3 \sqrt{3}) \: and \:(  - 3 \sqrt{3}  ) \\  \\ \small\green{\boxed{option \: (b) \: is \: the \: correct \: answer}}

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