Adjecent sides of rectangle are 7 cm and 24 cm find length of its diagonal
Answers
Answered by
167
Heya....
Here is your answer ----
In the given figure, ABCD is a rectangle with length 24 cm and breadth 7 cm.
Also, in the figure, BCD is a triangle right angled at D.
CD = Base = B = 24 cm
BD = Perpendicular = P = 7 cm
BC = Hypotenuse = H = H
So, according to Pythagoras Theorem,
Hypotenuse^2 = Base^2 + Perpendicular^2
(H)^2 = (B)^2 + (P)^2
=> (H)^2 = (24)^2 + (7)^2
=> (H)^2 = 576 + 49
=> (H)^2 = 625
=> H = √(625)
=> H = 25 cm
Diagonal = Hypotenuse = 25 cm
HOPE IT HELPS.....!!!
Here is your answer ----
In the given figure, ABCD is a rectangle with length 24 cm and breadth 7 cm.
Also, in the figure, BCD is a triangle right angled at D.
CD = Base = B = 24 cm
BD = Perpendicular = P = 7 cm
BC = Hypotenuse = H = H
So, according to Pythagoras Theorem,
Hypotenuse^2 = Base^2 + Perpendicular^2
(H)^2 = (B)^2 + (P)^2
=> (H)^2 = (24)^2 + (7)^2
=> (H)^2 = 576 + 49
=> (H)^2 = 625
=> H = √(625)
=> H = 25 cm
Diagonal = Hypotenuse = 25 cm
HOPE IT HELPS.....!!!
Attachments:
duragpalsingh:
Your class?
class 7 ^^" but why bhaiya?
Just askin'
:)
Answered by
82
length of adjacent sides are 7 cm and 24 cm respectively.
in, ΔBDC
Pythagoras Theorem!
H² = P² + B²
H² = 7² + (24)²
H² = 49 + 576
H = √625
H = 25
hence, the diagonal is 25 cm.
in, ΔBDC
Pythagoras Theorem!
H² = P² + B²
H² = 7² + (24)²
H² = 49 + 576
H = √625
H = 25
hence, the diagonal is 25 cm.
Attachments:
Similar questions