Question

af a and B are zeroes of the quadratic polynomial x2 - 6x + a find the value of 'a' if
3a + 2b = 20​

Answer 1

Given;

• quadratic eq. = x² - 6x + a
• roots = a & b
• 3a + 2b = 20

Thus product of zeoros = C/A

• ab = C/A
• ab = a/1
• b = 1

Thus substituting value of b in 3a + 2b = 20

• 3a + 2(1) = 20
• 3a = 20 - 2
• 3a = 18
• a = 6

#answerwithquality

#BAL

Answer 2

Answer:

the value of a is - 16

refer to the attachment for the solution