Question

AF, BD and CE are altitudes of ∆ ABC and are equal. Prove that ∆ ABC is an equilateral triangle.

Answer 1

Step-by-step explanation:

Solution :

<br>

(each 90)<br> AD=BE(given)<br>

(common)<br>

<br>

-(1)<br>

<br>

(each 90)<br>

(given)<br>

(common)<br>

(AAS)<br> AB=CB-(2)<br> from equation 1 and 2<br>

<br> Hence,

Answer 2

Answer:

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