Question

after 12 Years a man will be three times as old as his son the difference of their present ages is 30 years find their present ages

Answer 1

Answer: man = 33 yrs, son= 3 yrs

Step-by-step explanation:

let the man be x yrs old and son be y yrs old

ATQ     x+12=3(y+12) and x-y=30

= x = 30 + y

So, 30 + y + 12 = 3y + 36

= y + 42 = 3y + 36

= 2y = 6

= y = 3 yrs

and x = 30+3=33 yrs

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Answer 2

father=3x
son=x
difference=30
hence ,3x-x=30
2x=30
x=15
father=45
son =15