After 2 years of time, Paul will be 3 times as old as Alice. Presently he is 6 times as old. How old is Paul now?
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0
Paul = 6 * Alice ---- 1
Paul +2 = 3 (Alice + 2 )
Paul + 2 = 3 Alice + 6
Paul = 3 Alice + 4 ----- 2
equate equation 1 and 2:
6 * Alice = 3 * Alice + 4
3 * Alice = 4
Alice = 4/3 years = 16 months
Paul = 6 * 4/3 years = 8 years
Paul +2 = 3 (Alice + 2 )
Paul + 2 = 3 Alice + 6
Paul = 3 Alice + 4 ----- 2
equate equation 1 and 2:
6 * Alice = 3 * Alice + 4
3 * Alice = 4
Alice = 4/3 years = 16 months
Paul = 6 * 4/3 years = 8 years
Answered by
1
Let the present age of Paul be x and
Let the present age of Alice be y.
Then A.T.Q
1. x = 6y --------------------------------(1)
2. x +2 = 3×(y + 2)
x + 2 = 3y + 6 --------------------------(2)
Putting the value of x in (2)
6y - 3y = 4
3y= 4
y = 4/3
For x = 6y
x = 6 × 4/3
x= 8.
Hence the age of Paul is 8 years.
Let the present age of Alice be y.
Then A.T.Q
1. x = 6y --------------------------------(1)
2. x +2 = 3×(y + 2)
x + 2 = 3y + 6 --------------------------(2)
Putting the value of x in (2)
6y - 3y = 4
3y= 4
y = 4/3
For x = 6y
x = 6 × 4/3
x= 8.
Hence the age of Paul is 8 years.
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