Question

After an interval of one day, 161​th initial amount of a radioactive material remains in a sample. Then, its half-life is​

Answer 1

Answer:

First order decay:

N=N

o

e

−λt

Given at t=1 day, N(t)=

16

N

o

16

N

o

=N

o

e

−λ

λ=ln16 day

−1

Half life, t

1/2

=

λ

lln2

=

ln16

lln

=24/4=6 hours