Math, asked by pamjdv5020, 1 year ago

After every get-together every person present shakes the hand of every other person. If there were 105 handshakes in all, how many persons were present in the party?
A.16
B.15
C.13
D.14

Answers

Answered by 000khushi
1
let total no. of people present in the party be x.
then,
x(x-1)/2=105
x=15
Answered by vksundariob
3

Answer:


Step-by-step explanation: handshake relates to two persons only

Let the total persons be n only

Each person handshakes another person.

Hence, no. Of handshakes = nC2 = 105

n(n-1) /1 x 2 = 105

n^2 - n = 210

n^2 -n - 210 = 0

(n-15) (n+14) = 0

n = 15 or n = -14

no. Of persons were present = 15 only.



Similar questions