After every get-together every person present shakes the hand of every other person. If there were 105 handshakes in all, how many persons were present in the party?
A.16
B.15
C.13
D.14
Answers
Answered by
1
let total no. of people present in the party be x.
then,
x(x-1)/2=105
x=15
then,
x(x-1)/2=105
x=15
Answered by
3
Answer:
Step-by-step explanation: handshake relates to two persons only
Let the total persons be n only
Each person handshakes another person.
Hence, no. Of handshakes = nC2 = 105
n(n-1) /1 x 2 = 105
n^2 - n = 210
n^2 -n - 210 = 0
(n-15) (n+14) = 0
n = 15 or n = -14
no. Of persons were present = 15 only.
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