Question

When six fair coins are tossed simultaneously, in how many of the outcomes will at most three of the coins turn up as heads?
A.25
B.41
C.22
D.42

Answer 1

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♠️"B" 

1⃣ head = 6 
2⃣ heads = 6C2 = 15 
3⃣ heads = 6C3 = 20 

$\boxed{Total = 20+15+6 = 41 ways}$
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