after finding the hcf of any no. a and b how to represent the hcf in the form of ax+by??it's very confusing plzz help
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to find the value of x and y after finding the HCF of a and b you can just substitute the values they reqiure to form into their original self
here I am giving u an example:
hcf of 56 and 72 represent in the form ax+by:
72= 56*1+16
56= 16*3+8
16=8*2+0
u know by euclids divison lemma 8 is the HCF;
taking the hcf,
8= 56-16*3
8= 56-(72-56*1)*3
8= 56-3*72+56*3
8=56*4+-3*72
here you will find it in the form ax+by
where x= 4 and y= -3
here I am giving u an example:
hcf of 56 and 72 represent in the form ax+by:
72= 56*1+16
56= 16*3+8
16=8*2+0
u know by euclids divison lemma 8 is the HCF;
taking the hcf,
8= 56-16*3
8= 56-(72-56*1)*3
8= 56-3*72+56*3
8=56*4+-3*72
here you will find it in the form ax+by
where x= 4 and y= -3
after finding hcf in that reverse process i m getting confused can u explain in brief
I dont understand what you are trying to say!!
after finding hcf the next step
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