Calculate the pH of 10^-7 M of Ba(OH)2 solution
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10⁻⁷ moles of OH⁻ ions + 1 liter of water solution
There are 2 OH⁻ ions. So,
2 x 10⁻⁷ moles of OH⁻ ions + 10⁻⁷ moles of H₂O
Total OH⁻ ions = 3 x 10⁻⁷
= - log4 x 10⁻⁷
= - log3 + 7log 10
= - 0.477 + 7
= 6.523
pH = 14 - 6.523 = 7.477
Hope This Helps You!
There are 2 OH⁻ ions. So,
2 x 10⁻⁷ moles of OH⁻ ions + 10⁻⁷ moles of H₂O
Total OH⁻ ions = 3 x 10⁻⁷
= - log4 x 10⁻⁷
= - log3 + 7log 10
= - 0.477 + 7
= 6.523
pH = 14 - 6.523 = 7.477
Hope This Helps You!
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