Math, asked by ani184, 1 year ago

After incurring a loss of 33 1/3% a man had ₹18,600 ledt with him. What was the amount of money he originaly had?

Answers

Answered by ramaanjaneyulu2
21
18600 represents ( 100% - 33 1/3% ) of the original amount.
18600 = 66 2/3 % of the original amount
18600 = 2/3 of original amount
Mulitiply each side by 3
3(18600) = 3(2/3) original amount
3(18600) = 2 * original amount
Divide each side by 2
3(9300) = original amount
27900 = original amount
Answered by Raghav3333
17
hi

after  incurring a loss of 33 1/3% a man had ₹18,600

let the totl money be x

33 1/3%

=> 100/3%

money left = 18600

loss % = 100/3%


so money he had at first = 18600 * 100/100 - 100/3

=> 18600 *100/200/3

=>18600 *100*3/200

=> 93*300

=>27900 rs

hope it helps u

:0

Similar questions