After incurring a loss of 33 1/3% a man had ₹18,600 ledt with him. What was the amount of money he originaly had?
Answers
Answered by
21
18600 represents ( 100% - 33 1/3% ) of the original amount.
18600 = 66 2/3 % of the original amount
18600 = 2/3 of original amount
Mulitiply each side by 3
3(18600) = 3(2/3) original amount
3(18600) = 2 * original amount
Divide each side by 2
3(9300) = original amount
27900 = original amount
18600 = 66 2/3 % of the original amount
18600 = 2/3 of original amount
Mulitiply each side by 3
3(18600) = 3(2/3) original amount
3(18600) = 2 * original amount
Divide each side by 2
3(9300) = original amount
27900 = original amount
Answered by
17
hi
after incurring a loss of 33 1/3% a man had ₹18,600
let the totl money be x
33 1/3%
=> 100/3%
money left = 18600
loss % = 100/3%
so money he had at first = 18600 * 100/100 - 100/3
=> 18600 *100/200/3
=>18600 *100*3/200
=> 93*300
=>27900 rs
hope it helps u
:0
after incurring a loss of 33 1/3% a man had ₹18,600
let the totl money be x
33 1/3%
=> 100/3%
money left = 18600
loss % = 100/3%
so money he had at first = 18600 * 100/100 - 100/3
=> 18600 *100/200/3
=>18600 *100*3/200
=> 93*300
=>27900 rs
hope it helps u
:0
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