After inserting n A. Ms between 2 and 38, the sum of the resulting progression is 200. The value of n is (a) 10 (b) 8 (c) 9 (d) none of these
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Given : n AMs inserted between 2 and 38, sum of the resulting progression is 200.
To find : The value of n
Step-by-step explanation:
inserting n AMs between 2 and 38
=> Total Term = n + 2
First term = 2
Last term = 38
Sum = (number of terms/2) ( First term + last term)
= ((n + 2)/ 2) ( 2 + 38)
= 20n + 40
20n + 40 = 200
=> 20n = 160
=> n = 8
option b is correct
Term would be 2 , 6 , 10 , 14 , 18 , 22 , 26 , 30 , 34 , 38
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