Question

After painting his porch, Jamil has \dfrac1441​start fraction, 1, divided by, 4, end fractionof a can of paint remaining. The can has a radius of 888 cm and a height of 202020 cm. He wants to pour the remaining paint into a smaller can for storage. The smaller can has a radius of 555 cm.

What does the height of the smaller can need to be to hold all of the paint?

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Answer 1

Answer:

As we have given that the original can is having 1/4 th of paint remaining. So lets find the volume of the can:

Volume of cylinder(can) = πr²h

V = 22/7 x 8² x 20

V = 22/7 x 64 x 20

V = 22/7 x 1280

V = 4022.85 cm²

Now 1/4 th of the paint is remaining, so:

4022.85 x 1/4 = 1005.71 of paint is remaining.

Now this paint should be equal to volume of small can

Volume of small can is

22/7 x (5)² x h = 1005.71

h = 1005.71 x 7 / 22 x 25

h = 7,039.97‬ / 550

h = 12.79 cm (approx)

Answer 2

Answer:

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Step-by-step explanation:

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