Question

After perfectly inelastic collision between the two identical particles moving withbsame speed in different directions the speed of the particles become half the identical speed. The angle between velocities of the two before collision is

Answer 1

Hey mate,

● Answer-
θ = 120 °

● Explanation-
# Given-
v' = v/2
m' = 2m

# Solution-
We know that resultant momentum is-
p^2 = p1^2 + p2^2 + 2p1p2cosθ
(m'v')^2 = (mv)^2 + (mv)^2 + 2(mv)(mv)cosθ
(2mv/2)^2 = (mv)^2 (2 + 2cosθ)
cosθ = -1/2

Taking cos inverse-
θ = 120 °

Angle between two velocities before collision is 120°.

Hope this helps...

Answer 2

Answer:

hope this helps thank you