Question

After rationalising the denominator of 7/3root3 - 2root2
we get the denominator as
(a)13
(b)19
(C)5
(d)35​

Answer 1

Answer:

opinion (a) 13

from

A

B

C

D

ok

Answer 2

S O L U T I O N :

$\underline{\bf{Given\::}}$

After rationalization 7/3√3 - 2√2 .

$\underline{\bf{Explanation\::}}$

Using by rationalization method :

$\mapsto\tt{\dfrac{7}{3\sqrt{3} -2\sqrt{2} } }$

$\mapsto\tt{\dfrac{7}{3\sqrt{3} -2\sqrt{2} } \times \dfrac{3\sqrt{3} + 2\sqrt{2} }{3\sqrt{2} + 2\sqrt{2} } }$

$\mapsto\tt{\dfrac{7(3\sqrt{3} +2\sqrt{2}) }{(3\sqrt{3})^{2} -(2\sqrt{2})^{2}}\:\:\: [Using\:formula\:(a^2 - b^2 )]}$

$\mapsto\tt{\dfrac{7(3\sqrt{3} +2\sqrt{2}) }{(9 \times 3 - 4 \times 2)}}$

$\mapsto\tt{\dfrac{7(3\sqrt{3} +2\sqrt{2}) }{27 - 8}}$

$\mapsto\tt{\dfrac{7(3\sqrt{3} +2\sqrt{2}) }{19}}$

Thus,

The the denominator we will get 19 .

Option (b)