Math, asked by navsripathi9051, 10 months ago

After spending 2\5 of his money on cakes , mahesh had rs 45 left. how much money did he have at first

Answers

Answered by kartik2507
6

Answer:

Rs. 75

Step-by-step explanation:

let the total amount with Mahesh be x

he spent on cakes 2/5 of x

amount remaining with him = 45

x -  \frac{2x}{5}  = 45 \\  \frac{5x - 2x}{5}  = 45 \\ 5x - 2x = 45 \times 5 \\ 3x = 45 \times 5 \\ x =  \frac{45 \times 5}{3}  \\ x = 15 \times 5 \\ x = 75

therefore the money Mahesh had at first is Rs. 75

hope you get your answer

Answered by priyamandal923
1

Step-by-step explanation:

let the total amount with Mahesh be x

he spent on cakes 2/5 of x

amount remaining with him = 45

\begin{gathered}x - \frac{2x}{5} = 45 \\ \frac{5x - 2x}{5} = 45 \\ 5x - 2x = 45 \times 5 \\ 3x = 45 \times 5 \\ x = \frac{45 \times 5}{3} \\ x = 15 \times 5 \\ x = 75\end{gathered}x−52x=4555x−2x=455x−2x=45×53x=45×5x=345×5x=15×5x=75

therefore the money Mahesh had at first is Rs. 75

hope you get your answer

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