Math, asked by mrprakhardixit, 1 year ago

After working for 6 days, Ashok finds that
only 1/3 rd of the work has been done. He
employs Ravi who is 60% as efficient as
Ashok. How many days more would Ravi,
take to complete the work?​

Answers

Answered by sonuvuce
8

Answer:

20 days more will be required to complete the work

Step-by-step explanation:

In 6 days, the work done by Ashok = 1/3

Therefore, Ashok can complete a work = 18 days

In one day, work done by Ashok = 1/18

Efficiency of Ravi = 60%

Therefore,in a day, work done by Ravi = (1/18) × (60/100) = 1/30

Let the remaining days be n

Remaining work = 1-1/3 = 2/3

Therefore,

or, (n/30) = 2/3

or, (n/10) = 2

or, n = 20 days

Therefore B will take 20 days to complete the remaining work

Answered by khanamy413
0

Answer:

20 days more will be required to complete the work

Step-by-step explanation:

In 6 days, the work done by Ashok = 1/3

Therefore, Ashok can complete a work = 18 days

In one day, work done by Ashok = 1/18

Efficiency of Ravi 60%

Therefore,in a day, work done by Ravi (1/18) x (60/100) = 1/30

Let the remaining days be n

Remaining work = 1-1/3 = 2/3

Therefore,

or, (n/30) = 2/3

or, (n/10) = 2

or, n = 20 days

Therefore B will take 20 days to complete the remaining work

Step-by-step explanation:

i hope you understand

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