Question

Ag2CO3---》2Ag+CO2+1/2O2

1) Calculate weight of residue obtained when 55.2g of Ag2CO3 is heated

2)also calculate the total volume of gases evolved at STP.​

Answer 1

Explanation:     Ag2CO3 -> 2Ag + CO2 + 1/2O2

The equation is balanced. Now calculate the moles of Ag2CO3.

Moles of Ag2CO3 = 55.2/276 = 1/5 moles

Here residue is Ag and we are given that when 1 mole of Ag2CO3 is heated, it gives out 2 moles of Ag.

Therefore moles of Ag = 2*1/5 moles = 2/5 moles

Number of Moles = Given mass/Molar Mass

Given mass = Molar mass*Number of Moles

Mass of Ag = 276*2/5 = 110.4 g

2) Gases evolved are CO2 and O2.

And we are given that for every mole Ag2CO3 heated, it gives out 1 mole of CO2 and 1/2 moles of O2.

Moles of CO2 = 1*1/5 = 1/5

Moles of O2 = 1/2*1/5 = 1/10

Number of moles = Given volume/22.4

Given volume = Number of moles*22.4

Volume of CO2 = 1/5*22.4 = 4.48 litres

Volume of O2 = 1/10*22.4 = 2.24 litres

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