Question

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Answer 1

||✪✪ QUESTION ✪✪|| :--- Find the Median of the following observations :- 46,64,87,41,58,77,35,90,55,92,33 .

|| ★★ CONCEPT USED ★★ || :--

→ The median of a set of data is the middle-most number in the set. The median is also the number that is halfway into the set. To find the median, the data should first be arranged in order from least to greatest.

→ If there is an odd number of terms, the median is the center term. = (n+1)/2 th term.

→ If there is an even number of terms, add the two middle terms and divide by 2 = {(n/2 term)+(n/2+1) term}/2

___________________________

|| ✰✰ ANSWER ✰✰ ||

First lets arrange the observations in order ascending order ,,

→ 33, 35, 41, 46, 55, 58, 64, 77, 87, 90, 92 . = 11 Total = odd Number of Terms.

→ So,

Median = (n+1)/2

→ (11+1)/2 = 12/2

→ 6th term

→ 58. (Ans).

Hence, Median of given observation is 58.

Answer 2

$\huge\mathbb{SOLUTION:-}$

We have to find the median of given data

The data is

46,64,87,41,58,77,35,90,55,92,33

First Arrange the data in ascending order

33,35,41,46,55,58,64,77,87,90,92

• Total number of data is 11

• So median for odd number is
• (n+1)/2 term

Now

$\sf\underline{\purple{A.T.Q:-}}$

n=11

So median

$\sf\implies median=\dfrac{n+1}{2}term\\ \\ \sf\implies median=\dfrac{11+1}{2}=\cancel{\dfrac{12}{2}}=6\\ \\ \sf\implies median=6{}^{th}term\\ \\ \sf\implies median= 58$

$\boxed{\sf{Median=58}}$