Question

Agar in an open container is heated from 27 to 127 degree celsius amount in the in the fraction of the original amount of gas remaining in the container will be

Answer 1

Answer:

3/4

Explanation:

We know that, PV = nRT = constant

Where, Pressure P and Volume V are constant, in this case.

n is number of moles

R is gas constant

T is temperature

Given two temperature are 27 and 127 degree celcius

T1 = 27 + 273 = 300 K

T2 = 127 + 273 = 400 K

Therefore, n1T1= n2T2

n1×300=n2×400

n2=3n1 / 4

So, the fraction of moles of the remaining gas in the container after heating will be n2/ n1= 3/4

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