Age of a father 10years ago was thrice the age of his son.10 years hence,the fathers age will be twice that of his son.The ratio of their present ages is
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Let son's age be x (before 10 years)
Let father's age be 3x (before 10 years as he is 3 times his son's age)
2(x+20)=(3x+20)
2x+40=3x+20
40-20=3x-2x
20=1x
Father's age before 10 years=60
Son's age before 10 years=20
After 10 years
Father's age=70
Son's age=30
Hope this helped you
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