Math, asked by XYZz, 1 year ago

age of a person is twice the sum of the ages of his two sons and five years ago his age was thrice the sum of their ages. find his present age of

Answers

Answered by dkgolaclasses
31

DKG DEXTEROUS ZONE

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Answered by sharonr
46

Present age of person is 50 years old

Solution:

Let the present sum of ages of 2 sons be x

Given that,

Age of a person is twice the sum of the ages of his two sons

Present age of person = 2(x)

Present age of person = 2x

Five years ago his age was thrice the sum of their ages

Age of person 5 years ago = 2x - 5

Sum of ages of two sons 5 years ago = x - 5 - 5 = x - 10

Then, according to given,

Age of person 5 years ago = thrice the Sum of ages of two sons 5 years ago

2x - 5 = 3(x - 10)

2x - 5 = 3x - 30

3x - 2x = 30 - 5

x = 25

Therefore,

Present age of person = 2x = 2(25) = 50

Thus Present age of person is 50 years old

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