Question

age of Ais double of age C but 3/2times that of B. If sum of their ages is 52 years than what is the ratio of the ages of CandB?​

Answer 1

Answer:

Step-by-step explaunation:

Let the ages of A,B&C are x,y,z respectively

By given condtion,

x=2z and x=3/2y

so 2z =3/2y

y=4z/3

now,

x+y+z=52

substitute d values

2z+4z/3+z= 52

3z+4z/3=52

9z+4z/3=52

13z=52*3

z=52*3/13

z= 4*3

z=12

age of C is 12 yrs

y= 4z/3= 4*12/3

=16 yrs

age of B is 16 yrs

ratio of ages of C and B is 12:16 which is simplified as 3:4

Answer 2

The ratio of ages of C and B = 3 : 4

Given: Age of A is double of age C

Age of A is 3/2 times of B

Sume their age is 52 years

To find: Ratio of ages of C and B

Solution: Let ages of A, B and C are a, b and c respectively

From given data

Age of A is double of age C  

⇒  a = 2c

⇒ c =  $\frac{a}{2}$ _(1)  

Age of A is 3/2 times of B

⇒ a = $\frac{3}{2} (b)$    

⇒ b = $\frac{2}{3} a$ _(2)

Therefore, age of  a = a, b = $\frac{2}{3} a$, c = $\frac{a}{2}$  

Sum of age are 52 years

⇒ a + $\frac{2}{3} a$ + $\frac{a}{2}$  = 52

⇒ $\frac{6a+4a+3a}{6}$ = 52

⇒ 6a + 4a + 3a = 52 (6)

⇒ 13a = 312   ⇒   a = 24

Age of B = $\frac{2}{3} (24)$ = 2(8) = 16 years

Age of C = $\frac{a}{2}$ = $\frac{24}{2}$ = 12

Therefore, ratio of Ages of C and B = 12 : 16

⇒  3 : 4

The ratio of ages of C and B = 3 : 4

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