Age of leena and heena are in the ratio 7:5 . After Ten years their ages will be 9:7 . Find their present ages .
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Answered by
1
l:h=7:5=>5l=7h... (1)
(7l+10)/(5l+10)=(9/7)....(2)
solve both l and h values are 35 and 25 respectively
(7l+10)/(5l+10)=(9/7)....(2)
solve both l and h values are 35 and 25 respectively
Answered by
7
So, lets assume age of leena and heena to be 7x and 5x respectively.
After 10 years, there age will be-
Leena- 7x+10 (add 10 years)
Heena- 5x+10 (add 10 years)
According to the ques, after 10 years-
Leena- 9x
Heena-7x
So, lets combine both the equations and we get-
7x+10=9x {leena} ⇒5
5x+10=7x {heena}⇒5
leena=5*7=35 years
heena=5*5=25 years
After 10 years, there age will be-
Leena- 7x+10 (add 10 years)
Heena- 5x+10 (add 10 years)
According to the ques, after 10 years-
Leena- 9x
Heena-7x
So, lets combine both the equations and we get-
7x+10=9x {leena} ⇒5
5x+10=7x {heena}⇒5
leena=5*7=35 years
heena=5*5=25 years
Anonymous:
Oh! Thanks Riya!! ^_^.
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