Math, asked by thecheter, 8 months ago

Age of nandu is 10 more than that age of anu age of manu is 3 year more than twice the age of nandu. The sum of their age is 53. Find the their ages? (Hind: take the age of nandu as x​

Answers

Answered by manshamansha8879
1

Step-by-step explanation:

Nandu=10+Anu (1)

Manu=3+2×Nandu

Substitute equation (1)

Manu=3+2(10+Anu)

Anu+Nandu+Manu=53

Anu+10+Anu+3+2(10+Anu)=53

Anu+10+Anu+3+20+2Anu=53

4Anu=23=53

4Anu=20

Anu=5years.

Nandu=15years.

Manu=33years.

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Answered by Anonymous
6

\sf\underline{\purple{Given:-}}

Age of nandu is 10 more than that age of anu age

Manu is 3 year more than twice the age of nandu. The sum of their age is 53

\sf\underline{\purple{To\:Find:-}}

Their Ages</p><p>\: \: \:\:\: \: \circ \: \underline{\boxed{\red{\scriptsize{ \sf Hint: take \: the \: age \: of \: nandu \:  as \: x}}}} \\ </p><p>

\sf\underline{\purple{Solution:-}}

Nandu age is 10 years more than Anu

Manu is Twice 3 year more than nandu =

2x + 3

The sum of their age is = 53

4x = 53 + 10 - 3

So 4x = 60

x =\sf \frac{60}{4} </p><p></p><p>

So \:  \:  x = 15

Hence,

  • Age of Nandu = 15 years
  • Age of Anu = 5 years
  • Age of Manu = 33 years

Hope its help u

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