Question

Age of wife is reverse of husband.if the sum of digit is equal to one by 11 of difference

Answer 1

hii mate!!

let a = the 10's digit of the wife's age
let b = the units
:
A wife says if i reverse the digits of my age i will find the age of my husband .
10a+b = the wife's age
10b+a = husband's age
:
He is senior to me and the difference of our ages is equal to the 1/11 of the sum of our age.
(10a+b) + (10b+a) = 11((10b+a)-(10a+b))
11a + 11b = 11((10b+a)-(10a+b))
divide both sides by 11
a + b = (10b+a)-10a+b)
a + b = 10b - b + a - 10a
a + b = 9b - 9a
a + 9a = 9b - b
10a = 8b
a = 8b/10
a = .8b
Only one single digit solution possible
b=5, a=4.

hope it helps!!☺☺☺☺