Question

ages of a and b are in ratio 7:5.after 10yrs ratio of their ages 9:7.find their present ages

Answer 1

9/7=7+10/5+10
as according to q.
now,
9(5+10)=7(7+10)
45+90=49+70
135=119
135-119
16 answer

Answer 2

$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{\orange{R}}$

${\tt {\red {\huge {Given}}}}$

• Ratio of ages of A and B = 7:5

• 10yrs later ratio of ages of A and B = 9:7

${\tt {\red {\huge {To\: Find}}}}$

• Present age of A and B

${\tt {\red {\huge {Solution}}}}$

Let the age of A be 7x

then, age of B be 5x

Ten years later,

age of A = 7x + 10

age of B = 5x + 10

According to question,

$\bf {\orange\implies } \frac{7x + 10}{5x + 10} = \frac{9}{7}$

$\bf \: by \: cross \: multiplication$

$\bf {\orange\implies } (7x + 10)7 = 9(5x + 10)$

$\bf {\orange\implies } 49x + 70 = 45x + 90$

$\bf {\orange\implies } 49x - 45x = 90 - 70$

$\bf {\orange\implies } 4x = 20$

$\bf {\orange\implies } x = 20 \div 4$

$\bf {\orange\implies } x = 5$

Age of A ➨ 7x

= 7 × 5

= 35 years

Age of B ➨ 5x

= 5 × 5

= 25 years

hope it helps you....