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⭐Question in attachment plz solve⭐
U can solve any one and if possible then solve both
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#BeBrainly
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∫cosec²x sec ²x dx
∫(1+cot²x) sec ²x dx
∫( sec ²x + cosec²x) dx
∫ sec ²x dx + ∫cosec²x dx
tan x - cot x + C
Method 2=================================
∫cosec²x sec ²x dx
∫ dx
4 ∫ dx
4 ∫1 /(2 sinx cosx )² dx
4∫ 1/(sin2x)² dx
4∫ cosec² 2x dx
4(( -cot2x)/2)
= -2cot2x
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Anonymous:
wait , i will edit it ^^
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13
above is the answer. ....
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