Question

Ahola!!!!✌❤❤❤✌

⭐Question in attachment plz solve⭐

U can solve any one and if possible then solve both

Thanks☺

#BeBrainly

Answer 1

∫cosec²x sec ²x dx

∫(1+cot²x) sec ²x dx

∫( sec ²x + cosec²x) dx

∫ sec ²x dx + ∫cosec²x dx

tan x - cot x + C

Method 2=================================

∫cosec²x sec ²x dx

∫$\frac{1}{sin^{2} x} \frac{1}{cos^{2} x}$ dx

4 ∫$\frac{1}{4} \frac{1}{sin^{2} x} \frac{1}{cos^{2} x}$ dx

4 ∫1 /(2 sinx cosx )² dx

4∫ 1/(sin2x)²  dx 

4∫  cosec² 2x dx

4(( -cot2x)/2)

= -2cot2x

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Answer 2

above is the answer. ....