Question

ahoy!!

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if the position of a particle at any instant t is given by x = t^3, find the acceleration of the particle.

Answer 1

acceleration of a particle is the second derivative with respect to derivative
therefore acceleration is equal to
=6t

Answer 2

good afternoon!!
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time:12:05 PM 
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we are given x = $t^{3}$

differentiating both sides w.r.t time (t),  velocity:

$v = \frac{dx}{dt} = \frac{d}{dt} ( t^{3} )= 3 t^{2}$

acceleration:

$a = \frac{dv}{dt} = \frac{d}{dt} (3 t^{2} ) = 6t$


answer = 6t.

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