Question

Ahoy!


If the value is e.
Then why they wrote it being 1?

Answer 1

$\bf HELLO \: \: DEAR,$


$\bf = \frac{1}{x} \: \: Lt_{dx \to 0} log_{e}(1 + \frac{dx}{x})^\frac{x}{dx}$



$\bf \: \: \: \: \: \: \: \: \: \: \: \: \: given \: \: \bf \therefore \boxed{Lt_{dx \to 0}(1 + \frac{dx}{x})^\frac{x}{dx}} = e$


$\bf = \frac{1}{x} * log_{e} e$

$\bf = \frac{1}{x} * 1 \\ \\ \bf = \frac{1}{x}$



$\underline{\bf I \: \: HOPE \: \: ITS \: \: HELP \: \: YOU \: \: DEAR, \: \: THANKS}$

Answer 2

Hello Mahika Ji.

Please see the attached file !


Thanks !