find using distributive property
102x103
105x109 pls show full calculation
Answers
Answered by
6
105x109
(100+5)(100+9)
100x100+5+9x100+5x9
10000+14x100+45
10000+1400+45
11445
(100+5)(100+9)
100x100+5+9x100+5x9
10000+14x100+45
10000+1400+45
11445
abhinavbhadana2:
How are u
Answered by
7
1)102×103
=(100+2)(100+3)
=using identity ivth (x+a)(x+b)
=x^2+(a+b)x+ab
= 100^2+(2+3)100+(2)(3)
=10000+500+6
=10506
2)105×109
=(100+5)(100+9)
=100^2+(5+9)100+(5)(9)
=10000+1400+45
=11445
=(100+2)(100+3)
=using identity ivth (x+a)(x+b)
=x^2+(a+b)x+ab
= 100^2+(2+3)100+(2)(3)
=10000+500+6
=10506
2)105×109
=(100+5)(100+9)
=100^2+(5+9)100+(5)(9)
=10000+1400+45
=11445
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